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Re: "C" "K" "S" in PF solution
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I would expand Carolyn's Cabbalistic Equation:
C = K = S = Z (Z for Zembla) - since in Russian usage following German
or Dutch prononciation of S, many Germanic words that start with S are
transiterated with 3 (=Z) in Cyrillic, for example Brechtian term "Song"
became known as a "zong". And we recall that Zembla is Semberland.
Adding Cyrillic 3, we get also Pythagorean triad, the number of main
characters in PF.
C = K = S = 3 = Z
And then C = K = S = 3 = Z = C since Germanic Z is pronounced "ts", so
one goes a full zirkle.
I have to run to class otherwise "I could talk like this forever" (HMS
Pinafore)...
Victor Fet
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Visit Zembla: http://www.libraries.psu.edu/nabokov/zembla.htm
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C = K = S = Z (Z for Zembla) - since in Russian usage following German
or Dutch prononciation of S, many Germanic words that start with S are
transiterated with 3 (=Z) in Cyrillic, for example Brechtian term "Song"
became known as a "zong". And we recall that Zembla is Semberland.
Adding Cyrillic 3, we get also Pythagorean triad, the number of main
characters in PF.
C = K = S = 3 = Z
And then C = K = S = 3 = Z = C since Germanic Z is pronounced "ts", so
one goes a full zirkle.
I have to run to class otherwise "I could talk like this forever" (HMS
Pinafore)...
Victor Fet
Search the archive: http://listserv.ucsb.edu/archives/nabokv-l.html
Contact the Editors: mailto:nabokv-l@utk.edu,nabokv-l@holycross.edu
Visit Zembla: http://www.libraries.psu.edu/nabokov/zembla.htm
View Nabokv-L policies: http://web.utk.edu/~sblackwe/EDNote.htm